Submission #1201404


Source Code Expand

#include <bits/stdc++.h>
 
using namespace std;
 
typedef pair<string,int> P;
int N,Q,K,X,Y,W,Max,I,ans;
const int A=777777,B=123456;
const int INF=1000000009;
 
char C[A]; 
int parent[A],Parent[A],node[A],Node[A],O[26];
int G[A]; P H[A];
int J[A];
int JJ[A];
int Cnt[A];
int table[26][26];
vector<int> ch[A],L[A];
string S[A],T[A],U[A],V[A];
 
void dfs(int s,int e,int j,int p){
    int x=S[s][j]-'a'; int k=s;
  for(int i=s; i<=e; i++){
    if(x!=S[i][j]-'a'){
      dfs(k,i-1,j,p); k=i;
      x=S[i][j]-'a'; 
    }
  }
     //cout<<x<<" "<<j<<" "<<I++<<" "<<p<<endl;
     if(x<0) node[I]=26;
     else node[I]=x;
     if(j==0) parent[I]=A-1;
     else parent[I]=p;
     I++;
    if(x<0) return;
    if(j<Max) dfs(k,e,j+1,I-1);
    return;
}
int Pr(int k){
  int p=parent[k];
  if(p==A-1) return A-1;
  if(p>=0&&(parent[p]>=0&&ch[parent[p]].size()==1)){
    return Pr(p);
  }else{
    return p;
  }
}
int cnt(int k){
  if(L[k].size()==0){
    Cnt[k]=1;
    return 1;
  }
  for(int i=0; i<L[k].size(); i++){
    Cnt[k]+=cnt(L[k][i]);
  }
    return Cnt[k];
}
void make(int k){
  if(L[k].size()==0){
    J[X]=node[k]; JJ[X]=k;
    X++;
    return;
  }
  for(int i=0; i<L[k].size(); i++){
    make(L[k][i]);
  }
}
void Find(int k){
  if(W>=V[G[K-1]].size()) return;
  if(L[k].size()==0) return;
  int s;
  if(V[G[K-1]][W]-'a'>=0) s=V[G[K-1]][W]-'a'; 
  else s=-INF;
  int t;
  for(int i=0; i<L[k].size(); i++){
     if(s==node[L[k][i]]){
      t=L[k][i]; 
     }
     if(node[L[k][i]]<26&&table[s][node[L[k][i]]]==0){
      ans+=Cnt[L[k][i]];
     }
     if(node[L[k][i]]==26){
      ans++;
      Find(L[k][i]); 
     }
  }
  W++; Find(t); 
}
 
int main(){
 
cin>>N;
 
for(int i = 0; i < N; i++){
  scanf("%s", C);
  S[i] = string(C);
  if(S[i].size()>Max) Max=S[i].size();
}
 
for(int i = 0; i < N; i++) U[i]=S[i];
 
sort(S,S+N);
 
dfs(0,N-1,0,A-1);  
 
for(int i = 0; i < I; i++) if(parent[i]>=0) ch[parent[i]].push_back(i);
 
for(int i = 0; i < I; i++){
  int p=parent[i];
  if(p>=0&&ch[p].size()==1) node[i]=-INF;
}
 
for(int i = 0; i < I; i++){
  if(node[i]!=-INF){
    Parent[i]=Pr(i);
  }else{
    Parent[i]=-INF;
  }
}
 
for(int i = 0; i < I; i++){
  if(Parent[i]>=0) L[Parent[i]].push_back(i);
}
 
make(A-1); 
for(int i=0; i<N; i++){
  if(J[i]<=25){
    char c='a'+J[i];
    V[i]=c;
  }
  if(J[i]==26){
    V[i]="";
  }
  int k=JJ[i];
  while(1){
    if(Parent[k]==A-1) break;
    char c='a'+node[Parent[k]];
    V[i]=c+V[i];
    k=Parent[k];
  }
}
 
sort(V,V+N); 
for(int i=0; i<N; i++){
  H[i].first=U[i];
  H[i].second=i;
}
sort(H,H+N);
for(int i=0; i<N; i++){
  G[H[i].second]=i;
}

cnt(A-1);
 
cin>>Q;
 
for(int i=0; i<Q; i++){
  scanf("%d %s",&K,C);
  T[i] = string(C);
  for(int j=0; j<26; j++){
    O[T[i][j]-'a']=j;
  }
 for(int k=0; k<26; k++){
  for(int j=0; j<26; j++){
    table[k][j]=0;
  }
 }
 for(int k=0; k<26; k++){
  for(int j=0; j<26; j++){
   if(O[k]<=O[j]){
    table[k][j]=1;
   }else{
    table[k][j]=0;
   }
  }
 }
  X=0; I=0; ans=0; W=0;
  Find(A-1);
  printf("%d\n",ans+1);
}
 
return 0;
 
}

Submission Info

Submission Time
Task E - Lexicographical disorder
User momotaro1303
Language C++14 (GCC 5.4.1)
Score 0
Code Size 3208 Byte
Status RE
Exec Time 1012 ms
Memory 118272 KB

Compile Error

./Main.cpp: In function ‘int main()’:
./Main.cpp:94:17: warning: ignoring return value of ‘int scanf(const char*, ...)’, declared with attribute warn_unused_result [-Wunused-result]
   scanf("%s", C);
                 ^
./Main.cpp:157:22: warning: ignoring return value of ‘int scanf(const char*, ...)’, declared with attribute warn_unused_result [-Wunused-result]
   scanf("%d %s",&K,C);
                      ^

Judge Result

Set Name Sample All
Score / Max Score 0 / 0 0 / 1100
Status
AC × 2
AC × 40
RE × 2
Set Name Test Cases
Sample s1.txt, s2.txt
All 01.txt, 02.txt, 03.txt, 04.txt, 05.txt, 06.txt, 07.txt, 08.txt, 09.txt, 10.txt, 11.txt, 12.txt, 13.txt, 14.txt, 15.txt, 16.txt, 17.txt, 18.txt, 19.txt, 20.txt, 21.txt, 22.txt, 23.txt, 24.txt, 25.txt, 26.txt, 27.txt, 28.txt, 29.txt, 30.txt, 31.txt, 32.txt, 33.txt, 34.txt, 35.txt, 36.txt, 37.txt, 38.txt, 39.txt, 40.txt, s1.txt, s2.txt
Case Name Status Exec Time Memory
01.txt AC 445 ms 117760 KB
02.txt AC 445 ms 117760 KB
03.txt AC 449 ms 117760 KB
04.txt AC 448 ms 117760 KB
05.txt AC 346 ms 114688 KB
06.txt AC 277 ms 112768 KB
07.txt AC 258 ms 112384 KB
08.txt AC 245 ms 112256 KB
09.txt AC 233 ms 112256 KB
10.txt AC 219 ms 112256 KB
11.txt AC 320 ms 103040 KB
12.txt AC 338 ms 105344 KB
13.txt AC 365 ms 108288 KB
14.txt AC 257 ms 112128 KB
15.txt AC 228 ms 112384 KB
16.txt AC 220 ms 112256 KB
17.txt RE 141 ms 102016 KB
18.txt AC 886 ms 98304 KB
19.txt AC 888 ms 98304 KB
20.txt AC 1003 ms 98304 KB
21.txt AC 1005 ms 98304 KB
22.txt AC 1012 ms 98304 KB
23.txt AC 324 ms 105600 KB
24.txt AC 315 ms 103040 KB
25.txt AC 331 ms 105344 KB
26.txt AC 884 ms 98304 KB
27.txt AC 235 ms 99584 KB
28.txt AC 237 ms 100352 KB
29.txt AC 215 ms 99456 KB
30.txt AC 274 ms 103168 KB
31.txt AC 229 ms 101760 KB
32.txt AC 206 ms 100352 KB
33.txt AC 204 ms 102016 KB
34.txt AC 205 ms 101376 KB
35.txt AC 345 ms 102656 KB
36.txt AC 425 ms 118272 KB
37.txt AC 202 ms 106112 KB
38.txt AC 203 ms 106112 KB
39.txt AC 29 ms 88320 KB
40.txt RE 116 ms 86272 KB
s1.txt AC 29 ms 88320 KB
s2.txt AC 29 ms 88320 KB