Submission #1461124

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Source Code Expand

#pragma region include
#include <iostream>
#include <iomanip>
#include <stdio.h>

#include <sstream>
#include <algorithm>
#include <cmath>
#include <complex>

#include <string>
#include <cstring>
#include <vector>
#include <tuple>
#include <bitset>

#include <queue>
#include <complex>
#include <set>
#include <map>
#include <stack>
#include <list>

#include <fstream>
#include <random>
//#include <time.h>
#include <ctime>
#pragma endregion //#include
/////////
#define REP(i, x, n) for(int i = x; i < n; ++i)
#define rep(i,n) REP(i,0,n)
#define ALL(X) X.begin(), X.end()
/////////
#pragma region typedef
typedef long long LL;
typedef long double LD;
typedef unsigned long long ULL;
typedef std::pair<LL,LL> PLL;//
typedef std::pair<int,int> PII;//
#pragma endregion //typedef
////定数
const int INF = (int)1e9;
const LL MOD = (LL)1e9+7;
const LL LINF = (LL)1e18+20;
const double PI = acos(-1.0);
const double EPS = 1e-9;
/////////
using namespace::std;

void solve(){
	int N;
	cin >> N;
	vector<int> A(N+1,0);
	int MAX = 0;

	for(int i=1;i<=N;++i){
		cin >> A[i];
	}
	LL ans = 0;
	for(int i=1;i<=N;++i){
		int L,R;
		L = MAX + 1;//[0,i);
		R = A[i];
		if( L < R ){
			/*
			なるべくRを1にしたい(L以下)
			Lずつ削った時あまるのは
			[1,L-1]
			一回は必ず削れるので
			L+L-1をけずればよい
			*/
			int cnt = (R-1)/L;
			ans += cnt;
			R = 1;
		}
		//A[i] = R;
		MAX = max(MAX,R);
	}
	cout << ans << endl;
}

#pragma region main
signed main(void){
	std::cin.tie(0);
	std::ios::sync_with_stdio(false);
	std::cout << std::fixed;//小数を10進数表示
	cout << setprecision(16);//小数点以下の桁数を指定//coutとcerrで別	

	solve();
}
#pragma endregion //main()

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